5TH Grade Mathematics [Arithmetic Level 1] |
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N Z 1 <---> 0 2 <---> 1 3 <---> -1 4 <---> 2 5 <---> -2 6 <---> 3 7 <---> -3 . . .At this point it looks like there are more integers (Z) than natural numbers (N). But let's have a look at Hilbert's Hotel,
N Q
1 0/1
2 1/1
3 1/2
4 2/1
5 1/3
6 3/1
7 1/4
. . .
123 456 789 . 123 ||| ||| ||| | ||| ||| ||| ||| | |||__ Thousandths ||| ||| ||| | ||___ Hundredths ||| ||| ||| | |____ Tenths ||| ||| ||| | ||| ||| ||| |______ Decimal Point ||| ||| ||| ||| ||| |||__ Ones ||| ||| ||___ Tens ||| ||| |____ Hundreds ||| |||______ Thousands ||| ||_______ Ten Thousands ||| |________ Hundred Thousands |||__________ Millions ||___________ Ten Millions |____________ Hundred Millions
| .
. 1
acre
of arable land
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| . | . |
| 1/10 or 0.1 for corn |
1/10 or 0.1 for corn |
| 1/10 or 0.1 for corn |
1/10 or 0.1 for corn |
| 1/10 or 0.1 for pig sty |
1/10 or 0.1 for beans |
| 1/10 or 0.1 for beans |
1/10 or 0.1 for beans |
| 1/10 or 0.1 for beans |
1/10 or 0.1 for beans |
| 1/10 or 0.1 for corn |
1/10 or 0.1 for corn |
| 1/10 or 0.1 for corn |
1/10 or 0.1 for corn |
|
+ | 1 2 3 4 5 6 7 8 9 10
--+---------------------------------------
10 |11 12 13 14 15 16 17 18 19 20
| ^
20 |21 22 23 24 25 26 27 28 29 30 |
| |
30 |31 32 33 34 35 36 37 38 39 40 subtract 10
| |
40 |41 42 43 44 45 46 47 48 49 50 |
| <--subtract 1 -------- add 1-->
50 |51 52 53 54 55 56 57 58 59 60 |
| |
60 |61 62 63 64 65 66 67 68 69 70 add 10
| |
70 |71 72 73 74 75 76 77 78 79 80 |
| v
80 |81 82 83 84 85 86 87 88 89 90
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90 |91 92 93 94 95 96 97 98 99 100
1234 |add 4 + 8
+5678 <----|the answer is 12
-------
1 <----|carry the 1
1234
+5678
-------
2 <----|write the 2
1
1234 |add 3 + 7
+5678 <----|the answer is 10, add the 1 you carried, the answer is 11
-------
2
11 <----|carry the 1 (the second to the right)
1234
+5678
-------
12 <----|write the two
11
1234 |add 2 + 6
+5678 <----|the answer is 8 add the 1 you carried, the answer is 9
-------
12
11 <----|no number to carry this time because 9 has only one digit
1234
+5678
-------
912 <----|write the nine
11
1234 |add 1 + 5
+5678 <----|the answer is 6
-------
6912 <----|write the six and you are done
The same procedure can be extended to numbers with decimals,
123.45
+678.9
---------
|
|_______note the decimal point
123.45
+678.9
---------
5
1
123.45
+678.9
---------
.35
11
123.45
+678.9
---------
2.35
111
123.45
+678.9
---------
802.35
Note that the decimal points in the addends must be aligned.
984 <----|subtract 6 from 4? cannot be done
-546 |borrow 1 from the tens place, 4 becomes 14
------
8 becomes 7
|4 becomes 14
||
984 <----|subtract 6 from 14
-546
------
8 <----|the answer is 8
984 <----|subtract 4 from 7
-546 |no need to borrow from the hundreds place
------
38 <----|the answer is 3
984 <----|subtract 5 from 9
-546
------
38 <----|the answer is 4 and you are done
1 0 0
- 9 9
------
We can't subtract 9 from 0, so we go to the tens place to borrow a ten. Since
there are no tens to borrow, we have to go to the hundreds place to borrow a hundred.
Since there is only a 1 in the hundreds place, this turns into a zero,
0 10
/ /
1 0 0
- 9 9
------
Now we can take one from the tens, turning the 0 into 10 ones, from which we can subtract 9,
0 9 10
/ / /
1 0 0
- 9 9
------
1
Finally, we can subtract the 9 tens,
0 9 10
/ / /
1 0 0
- 9 9
------
0 0 1
The 9 in the tens place came from the 10 tens we borrowed from one hundred), minus the 1 ten that was borrowed
from it by the ones place.
99
+ 1
----
and 9 in the tens place will turn into a 10.
x | 2 3 4 5 6 7 8 9 10 11 12
--+------------------------------------------
2 | 4 6 8 10 12 14 16 18 20 22 24
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3 | 6 9 12 15 18 21 24 27 30 33 36
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4 | 8 12 16 20 24 28 32 36 40 44 48
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5 |10 15 20 25 30 35 40 45 50 55 60
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6 |12 18 24 30 36 42 48 54 60 66 72
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7 |14 21 28 35 42 49 56 63 70 77 84
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8 |16 24 32 40 48 56 64 72 80 88 96
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9 |18 27 36 45 54 63 72 81 90 99 108
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10 |20 30 40 50 60 70 80 90 100 110 120
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11 |22 33 44 55 66 77 88 99 110 121 132
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12 |24 36 48 60 72 84 96 108 120 132 144
1 <--| 3 X 6 = 18
9876 X 3 | write the 8 (unit) and carry the 1 (ten) over
----------- |
8 <--|
21 <--| 3 X 7 = 21
9876 X 3 | add the 1 left from previous operation
----------- | 21 + 1 = 22, Note that you add the 1 (ten) to the units
28 <--| write the 2 and carry the 2 over
221 <--| 3 X 8 = 24
9876 X 3 | add the 2 left from previous operation
----------- | 24 + 2 = 26
628 <--| write the 6 and carry the 2 over
221 <--| 3 X 9 = 27
9876 X 3 | add the 2 left from previous operation
----------- | 27 + 2 = 29
29628 <--| write the 29 and you are done
345 X 607
---------------
2415 <-- 345 X 7
000 <-- shift one space to the right, 345 X 0 = 000
2070 <-- shift one space to the right, 345 X 6 = 2070
---------------
209415 <-- add up all results
This has the advantage of being fairly accurate when performed by a skilled person but requires memorization of a multiplication table, neat penmanship and mental focus.
Count the number of decimal places in the multiplier and the multiplicand,
34.5 X 60.7
| |________ one decimal place in the multiplier
|_______________ one decimal place in the multiplicand
that is two decimal places total
Do the multiplication as if the decimal points were not there,
34.5 X 60.7
---------------
2415 <-- 345 X 7
000 <-- shift one space to the right, 345 X 0 = 000
2070 <-- shift one space to the right, 345 X 6 = 2070
---------------
209415 <--| add up all results
2094.15 <--| shift the decimal point
| by the total number of decimal places
| in the multiplier and the multiplicand
6 ÷ 3 = 2 | | |__quotient | |______divisor |__________dividend 6 <--dividend --- = 2 <--quotient 3 <--divisorDivision is not a commutative operation. Switching the dividend and the divisor will likely give a different quotient. For Example:
Start with the first two digits [54]
4 <-- 12 goes 4 times into 54 and the remainder is 6
_______
548184 )12
-48 <-- Subtract [4 X 12 = 48] from 54
4
_______
548184 )12
-48
68 <-- Bring down the next digit
45 <-- 12 goes 5 times into 68 and the remainder is 8
_______
548184 )12
-48
68
-60 <-- Subtract [5 X 12 = 60] from 68
81 <-- Bring down the next digit
456 <-- 12 goes 6 times into 81 and the remainder is 9
_______
548184 )12
-48
68
-60
81
-72 <-- Subtract [6 X 12 = 72] from 81
98 <-- Bring down the next digit
4568 <-- 12 goes 8 times into 98 and the remainder is 2
_______
548184 )12
-48
68
-60
81
-72
98
96 <-- Subtract [8 X 12 = 96] from 98
24 <-- Bring down the next digit
45682 <-- 12 goes 2 times into 98 and the remainder is 0
_______
548184 )12
-48
68
-60
81
-72
98
96
24
-24 <-- Subtract [8 X 2 = 24] from 24
0 <-- You are done
________
28 )8
3 <----|8 goes 3 times into 26 and the ramainder is 2
________
28 )8
-24 <----|subtract [3 X 8 = 24] from 26
4
3. <----|add a decimal point
________ |
28 )8 |
-24 |
40 <----|add a 0 to the 4 and make it 40
3.5 <----|8 goes 5 times into 40
________
26 )8
-24
40
-40 <----|subtract [5 X 8 = 40] from 40
00 <----|the remainder is zero, so you are done.
________
10 )3
_
3.33
________
10 )3
10
10
1
1 000 000.0 1.000 000 0 |-------| <--the decimal point is shifted 6 places to the right ||| ||| 123 456 Thus, 1 000 000.0 = 1.000 000 0 X 106 0.000 000 10 0.000 000 1.0 |---------| <--the decimal point is shifted 7 places to the left ||| ||| | 123 456 7 Thus, 0.000 000 1 = 1.0 X 10-7 432 000.0 4.32 000 0 |------| <--the decimal point is shifted 5 places to the right ||| || 123 45 Thus, 432 000.0 = 4.32 X 105Note that 4.32 X 105 and 4.320000 X 105 have the same value. The way the number is written depends on the number of significant digits, which means how many digits are good or reflect the value of real data. The concept of significant digits is beyond the scope of this text but let's give an example,
$100.253 $1.00 253 |--| <--the decimal point is shifted 2 places to the right 12 $100.253 = $1.0025 X 102The final answer is one digit short compared to the initial quantity. This is because we can recover a meaningful number without the last digit,
$250.25 $2.50 25 |--| <--the decimal point is shifted 2 places to the right 12 $250.25 = $2.50 X 102Let's recover the number,
| 1'st | PARENTHESES | Grouping symbols are always done from the innermost set outward. |
| 2'nd | EXPONENTS | Remember
applying an exponent is different than just multiplying.
Ex: 23 means 2 x 2 x 2 = 8 |
| 3'rd | MULTIPLY | These operations are done in the order they appear from left to right. They are done together because they have the SAME IMPORTANCE. |
| DIVIDE | ||
| 4'th | ADD | Here again we have two operations of the SAME IMPORTANCE. These are done in the order that they appear from left to right. |
| SUBTRACT |
| Parentheses | |||
| Exponents | |||
| Multiply or Divide | |||
| Add or Subtract | |||
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| Example 1: | Evaluate 52 x 24 | ||||||||
| Solution: |
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| Example 2: | Evaluate 289 - (3 x 5)2 | |||||||||
| Solution: |
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| Example 3: | Evaluate 8 + (2 x 5) x 34 ÷ 9 | ||||||||||||||
| Solution: |
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5
---
112
The top (or first) number is called the numerator. The number on bottom
(or second number) is called the denominator. In the fraction 5/112, "5" is the numerator
and "112" is the denominator.
9/3 = 3
8/4 = 2
10/3 = 3 1/3
22/7 = 3 1/7
You can use either an improper fraction or a mixed fraction to show the same amount. For example,
Divide: 11 ÷ 4 = 2 with a remainder of 3
Write down the (2)
__________________
| 3 <------- write down the remainder (3)
+-------------> 2 ---
4 <------- above the denominator (4)
Multiply the whole number by the denominator: 3 × 5 = 15
Add the numerator to that: 15 + 2 = 17
Write down the (17)
___________________
|
+-------------> 17
---
5 <------- above the denominator (5)
Fractions whose numerator and denominator are divisible by the same digit can be reduced by
dividing both the numerator and denominator by this digit. This does not change the value of the fraction
16/32 = 1/2
16/32 = 8/16 = 4/8 = 1/2
[1] Multiply the numerators together; [2] Multiply the denominators together; and [3] Place the product of the numerators over the product of the denominators.For example:
2 4 [2 x 4] 8
---- x ---- = ------------ = -----
3 5 [3 x 5] 15
1 2 [1 x 2] 2
---- x ---- = ------------ = -----
3 7 [3 x 7] 21
2 4 [2 x 5] 10 5
---- ÷ ---- = ------------ = ----- = ----
3 5 [3 x 4] 12 6
1 2 [1 x 7] 7
---- ÷ ---- = ------------ = -----
3 7 [3 x 2] 6
3 4 [3 + 4] 7 5
---- + ---- = ------------ = ----- = ----
3 3 3 3 6
5 2 [5 + 2] 7
---- + ---- = ------------ = ----- = 1
7 7 7 7
As a rule, when working with fractions -- you can't add fractions with different denominators.
This means that, in order for two fractions to be added together, the bottom numbers must be the same.
More than two fractions can be added together at one time as long as
they all have the same denominator,
3 4 3 10
---- + ---- + -------- = -----
3 3 3 3
5 2 4 11
---- + ---- + ------ = -----
7 7 7 7
9 5 4
---- - ---- = -----
12 12 12
4 2 2
---- - ---- = ------
18 18 18
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12 inches (in) = 1 foot (ft)
3 feet = 1 yard (yd)
5280 feet = 1 mile (mi)
1760 yards = 1 mile
Examples,
1 ft
48 in X ------ = 4 ft
12 in
Here we used the fact that 1 ft = 12 in. These two numbers are put into a conversion factor in such a
way that the units that are not needed will cancel.
3 ft
4 yd X ------ = 12 ft
1 yd
Here we used 3 ft = 1 yd.
5280 ft
2 mi X --------- = 10560 ft
1 mi
Here we used 5280 ft = 1 mi.
1 mi
7040 yd X --------- = 4 mi
1760 yd
Here we used 1760 yd = 1 mi.
If we measure the amount of space occupied by anything that contains matter, we are measuring volume. How much volume something (such as a cup or a box) can hold is called its capacity.
The volumes of solid objects is usually given in cubic units (such as cubic centimeters or cubic feet). For historical reasons, the volume of liquids is usually given in liters, gallons, quarts, and other fluid measures. The table below gives some English and metric volume units.
Within the customary system, the common units for measuring capacity are fluid ounces, cups, pints, quarts, and gallons.
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1 cup (c.) |
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8 fluid ounces (fl. oz.) |
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1 pint (pt.) |
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2 cups (c.) |
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1 quart (qt.) |
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4 cups (c.) |
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1 quart (qt.) |
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2 pints (pt.) |
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1 gallon (gal.) |
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4 quarts (qt.) |
8 fl. oz.
2 c X --------- = 16 fl. oz.
1 c
Here we used the fact that 1 cup = 8 fluid ounces.
1 gal
24 qt X --------- = 6 gal.
4 qt
Here we used the fact that 1 gallon = 4 quarts.
Commonly referred to as "weight", although mass and weight have different meanings
in the scientific world.
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1 lb
24 oz. X --------- = 1.5 lb.
16 oz
Here we used the fact that 1 pound = 16 ounces. The answer could have also been written as 1 lb 8 oz
because 0.5 or half a pound = 8 ounces.
1 kg
22 lb X --------- = 10 kg.
2.2 lb
Here we used the fact that 1 kilogram = 2.2 pounds.
|
-->
AB
Note how the arrow heads denotes the direction the ray extends in: there is no arrow head over the endpoint.
--> -->
For example: Rays HG and AB
A
\ | / +-------
\ | / /
\ A |A / A /
+------- +------- +------- /
obtuse right acute reflex <----- angle
>90 90 <90 >180 <--- degrees
The reflex angle looks like any of the others, but it is measured around the back.
We can specify an angle by using a point on each ray and the vertex. The angle below may be specified as angle ABC or as angle CBA; you may also see this written as 〈ABC or as 〈CBA. Note how the vertex point is always given in the middle.
A
\
\
\
+--------- C
B
Two angles are called complementary angles if the sum of their degree measurements equals 90 degrees.
One of the complementary angles is said to be the complement of the other. For Example,


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A right triangle has one other angle that is 350. What is the size of the third angle? |
a
+
/ .
/ .
/ .
b +-------+ c
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Is it possible for a triangle to have more than one obtuse angle?
a b
+----+
/ .
/ .
/ .
/.
c +
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An equilateral triangle has one side that measures 5 in. What is the size of the angle opposite that side?
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An isosceles triangle has one angle of 460. What are the sizes of the other two angles?
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A B
+----------+
| |
| |
+----------+
D C
This rectangle is named ABCD
--> --> --> -->
Its line segments AB, BC, CD and DA
Its vertices are A, B, C, and D
As shown in the following figure, polygons are classified according to the number of sides.